Applications of Derivatives

Increasing and Decreasing Functions

Understand

A function is strictly increasing on an interval if \(x_1<x_2\Rightarrow f(x_1)<f(x_2)\), and strictly decreasing if \(x_1<x_2\Rightarrow f(x_1)>f(x_2)\). For differentiable functions:

  • \(f\,'(x)>0\) for all \(x\) in an open interval ⇒ \(f\) is strictly increasing there;
  • \(f\,'(x)<0\) ⇒ strictly decreasing;
  • \(f\,'(x)=0\) throughout ⇒ constant.

Finding the intervals

  1. Find \(f\,'(x)\) and solve \(f\,'(x)=0\) (these points split the real line).
  2. Test the sign of \(f\,'(x)\) in each interval.
  3. Positive ⇒ increasing, negative ⇒ decreasing.

Example: \(f(x)=x^3-6x^2+9x+1\), \(f\,'(x)=3(x-1)(x-3)\). Increasing on \((-\infty,1]\) and \([3,\infty)\), decreasing on \([1,3]\).

1351xy
\(f(x)=x^3-6x^2+9x+1\): rises, falls on \([1,3]\), rises again.

Key Concepts

  • f′ > 0 ⇒ increasing; f′ < 0 ⇒ decreasing.
  • Critical points split the domain into test intervals.
  • Isolated zeros of f′ do not stop strict monotonicity (e.g. x³).

Key Points

Sign chart

Mark the zeros of \(f\,'\) on a number line and test one point in each interval; the sign of \(f\,'\) gives increasing (+) or decreasing (−).

Solved Examples

Intervals of monotonicity

\(f(x)=2x^3-3x^2-12x+6\).

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Topic Summary

Solve f′(x) = 0, make a sign chart, and read off the intervals.

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