Continuity test
LHL = RHL = \(f(c)\). For piecewise functions, test only the joining points.
Continuity and Differentiability
A function \(f\) is continuous at \(x=c\) if \(f(c)\) is defined and \(\displaystyle\lim_{x\to c}f(x)=f(c)\). In practice we check three numbers:
\[\text{LHL}=\lim_{x\to c^-}f(x),\qquad \text{RHL}=\lim_{x\to c^+}f(x),\qquad f(c)\]
If all three are equal, \(f\) is continuous at \(c\); otherwise it is discontinuous there. A function is continuous (on an interval) if it is continuous at every point of it.
Piecewise functions. Each piece is usually continuous on its own interval, so only the "joining points" need checking. To make \(f(x)=\begin{cases}kx+1,&x\le2\\3x-1,&x>2\end{cases}\) continuous, equate the one-sided limits at 2: \(2k+1=5\Rightarrow k=2\).
LHL = RHL = \(f(c)\). For piecewise functions, test only the joining points.
Find \(k\) so that \(f(x)=\begin{cases}\frac{\sin 5x}{x},&x\neq0\\k,&x=0\end{cases}\) is continuous at 0.
\(\lim_{x\to0}\frac{\sin5x}{x}=5\lim\frac{\sin5x}{5x}=5\), so \(k=5\).
A fresh set of questions from this topic. Change answers freely – solutions appear after you submit.
Start PracticeCheck the three values LHL, RHL and f(c). Use algebra of continuous functions to avoid checking every point.
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