Adjoint identity
\[A(\operatorname{adj}A) = (\operatorname{adj}A)A = |A|\,I\]
Consequences: \(A^{-1} = \dfrac{\operatorname{adj}A}{|A|}\) and \(|\operatorname{adj}A| = |A|^{n-1}\).
Determinants
The adjoint of a square matrix is the transpose of its cofactor matrix: \(\operatorname{adj}A = [A_{ij}]^T\).
The fundamental identity is
\[A(\operatorname{adj}A) = (\operatorname{adj}A)A = |A|\,I.\]
So if \(|A| \ne 0\), \(A\) is invertible and
\[A^{-1} = \frac{1}{|A|}\operatorname{adj}A.\]
If \(|A| = 0\), \(A\) has no inverse.
\[A(\operatorname{adj}A) = (\operatorname{adj}A)A = |A|\,I\]
Consequences: \(A^{-1} = \dfrac{\operatorname{adj}A}{|A|}\) and \(|\operatorname{adj}A| = |A|^{n-1}\).
\[A^{-1} = \frac{1}{|A|}\operatorname{adj}A, \quad |A| \ne 0\]
Also \(|A^{-1}| = 1/|A|\).
\[A(\operatorname{adj}A)=(\operatorname{adj}A)A=|A|I,\qquad |\operatorname{adj}A|=|A|^{n-1}\]
Before finding an inverse, evaluate |A|. If it is zero, the inverse does not exist – say so and stop.
Taking the cofactor matrix itself as adj A.
Correct: \(\operatorname{adj}A = (\text{cofactor matrix})^T\). The (1,2) entry of adj A is the cofactor \(A_{21}\).
A fresh set of questions from this topic. Change answers freely – solutions appear after you submit.
Start Practice\(\operatorname{adj}A\) = transpose of cofactor matrix. \(A\,\operatorname{adj}A = |A|I\). \(A^{-1} = \operatorname{adj}A / |A|\) when \(|A| \ne 0\). \(|\operatorname{adj}A| = |A|^{n-1}\).
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