Exponential growth/decay
Differential Equations · Variables Separable Method\[\frac{dP}{dt}=kP\;\Rightarrow\;P=P_0e^{kt}\]
A differential equation links an unknown function with its derivatives: \(\frac{dy}{dx}=ky\) says "the rate of growth is proportional to the size". Such equations model population growth, cooling, radioactive decay, interest and motion. In this chapter you will classify differential equations by order and degree, check solutions, and solve three important first-order types: variables separable, homogeneous and linear.
\[\frac{dP}{dt}=kP\;\Rightarrow\;P=P_0e^{kt}\]
\[y=vx,\quad \frac{dy}{dx}=v+x\frac{dv}{dx}\]
\[\frac{dy}{dx}+Py=Q:\quad \text{IF}=e^{\int P\,dx},\quad y\,\text{IF}=\int Q\,\text{IF}\,dx+C\]
If a derivative appears inside sin, cos, e, log (e.g. \(y''+e^{y'}=0\)), the equation is not a polynomial in derivatives and its degree is not defined.
The general solution of an nth-order equation has exactly n arbitrary constants.
For \(\left(1+(y')^2\right)^{3/2}=y''\), square both sides first: the degree is 2, not \(\frac23\) or undefined.
After \(\log|y|=x^2+C\), write \(y=Ae^{x^2}\) – the constant multiplies, it does not add.
For \(x\frac{dy}{dx}+2y=x^2\), divide by \(x\) first: \(P=\frac2x\), \(\text{IF}=x^2\) – not \(e^{\int2\,dx}\).
Solve \(\frac{dy}{dx}=\frac{y}{x}+\frac{x}{y}\).
\(y=vx\): \(x\frac{dv}{dx}=\frac1v\Rightarrow v\,dv=\frac{dx}x\Rightarrow\frac{v^2}2=\log|x|+C\Rightarrow y^2=2x^2(\log|x|+C)\).
Solve \(\frac{dy}{dx}+y=e^{x}\).
\(\text{IF}=e^x\). \(ye^x=\int e^{2x}dx=\frac{e^{2x}}2+C\Rightarrow y=\frac{e^x}2+Ce^{-x}\).
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