Standard form of an LPP
Linear Programming · Terminology and Formulation\[\text{Optimise } Z=px+qy\ \text{ subject to }\ a_ix+b_iy\ (\le,\ \ge)\ c_i,\quad x\ge0,\ y\ge0\]
Chapter 12 · Linear Programming
Businesses, farms and kitchens constantly ask “how much of each should we make or buy to get the best result under our limits?” Linear programming answers such questions when the goal and the limits are linear. In this chapter you will learn the vocabulary, translate word problems into mathematical form, and solve two-variable problems by the graphical (corner-point) method.
\[\text{Optimise } Z=px+qy\ \text{ subject to }\ a_ix+b_iy\ (\le,\ \ge)\ c_i,\quad x\ge0,\ y\ge0\]
If an LPP has an optimal value, it is attained at a corner point of the feasible region. A bounded feasible region always has both a maximum and a minimum value of \(Z\).
To decide which side of \(ax+by=c\) to shade, substitute a point not on the line (usually the origin). If it satisfies the inequality, shade its side.
If \(Z\) has the same optimal value at two adjacent corners, all points on the edge joining them are optimal.
“At least” means ≥ and “at most” means ≤. Reversing one inequality changes the whole feasible region.
On an unbounded region the largest value in the table need not be a maximum. Draw \(px+qy>M\) and check whether it meets the region.
Maximise \(Z=60x+90y\) subject to \(x+2y\le16,\ x+y\le10,\ x,y\ge0\).
Corner points: \((0,0),(10,0),(4,6),(0,8)\). Values: 0, 600, 780, 720. The region is bounded, so \(Z_{\max}=₹780\) at \((4,6)\): make 4 mugs and 6 bowls.
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