Relations and Functions

Equivalence Relations

Understand

A relation that is reflexive, symmetric and transitive is called an equivalence relation. It captures the idea of "being alike in some respect": having the same remainder on division by 5, being parallel, being similar triangles, having the same birthday month.

Equivalence classes

For an equivalence relation \(R\) on \(A\), the equivalence class of \(a\) is \([a]=\{x\in A : x\,R\,a\}\). Two facts make classes useful:

  • Every element lies in its own class (reflexivity).
  • Two classes are either identical or disjoint. So the classes partition \(A\) into non-overlapping pieces.

Example: on \(\mathbb{Z}\), \(a\,R\,b \iff 3 \mid (a-b)\). The classes are \([0]=\{\dots,-3,0,3,6,\dots\}\), \([1]=\{\dots,-2,1,4,\dots\}\) and \([2]=\{\dots,-1,2,5,\dots\}\) – exactly three classes, one for each remainder.

Proving a relation is an equivalence relation

  1. Reflexive: show \(a\,R\,a\) for an arbitrary \(a\).
  2. Symmetric: assume \(a\,R\,b\), deduce \(b\,R\,a\).
  3. Transitive: assume \(a\,R\,b\) and \(b\,R\,c\), deduce \(a\,R\,c\).

Key Concepts

  • Equivalence = reflexive + symmetric + transitive.
  • Classes are disjoint or equal; together they cover the whole set.
  • "Congruence modulo n" on \(\mathbb{Z}\) has exactly \(n\) classes.

Formula Bank

Congruence modulo n

\[a\equiv b \pmod n \iff n\mid(a-b)\]

Key Points

Classes partition the set

Equivalence classes are either identical or disjoint, and their union is the whole set.

Solved Examples

Equivalence classes mod 4

On \(A=\{1,2,\dots,9\}\), \(a\,R\,b \iff 4\mid(a-b)\).

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Topic Summary

An equivalence relation groups a set into disjoint classes of mutually related elements. Always check all three properties with general elements.

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