Symmetric + skew-symmetric split
\[A = \tfrac12(A + A^{T}) + \tfrac12(A - A^{T})\]
The first part is symmetric, the second skew-symmetric. Works for every square matrix.
Matrices
A square matrix \(A\) is symmetric if \(A^T = A\) (i.e. \(a_{ij} = a_{ji}\)), and skew-symmetric if \(A^T = -A\) (i.e. \(a_{ij} = -a_{ji}\)).
In a skew-symmetric matrix, putting \(i = j\) gives \(a_{ii} = -a_{ii}\), so every diagonal entry is 0.
For any square matrix \(A\):
\[A = \tfrac12(A + A^{T}) + \tfrac12(A - A^{T})\]
The first part is symmetric, the second skew-symmetric. Works for every square matrix.
From \(a_{ii} = -a_{ii}\), every diagonal entry of a skew-symmetric matrix is 0.
An \(n\times n\) symmetric matrix is fixed by \(\frac{n(n+1)}{2}\) entries; a skew-symmetric one by \(\frac{n(n-1)}{2}\) entries (its diagonal is zero).
Express \(A = \begin{bmatrix} 1 & 2 & 4 \\ 6 & 8 & 1 \\ 3 & 5 & 7 \end{bmatrix}\) as the sum of a symmetric and a skew-symmetric matrix.
Final Answer: \(A = P + Q\) as shown
A fresh set of questions from this topic. Change answers freely – solutions appear after you submit.
Start Practice\(A^T = A\): symmetric. \(A^T = -A\): skew-symmetric (zero diagonal). \(A = P + Q\) with \(P = \tfrac12(A + A^T)\), \(Q = \tfrac12(A - A^T)\).
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