Dot product and projection
\[\vec a\cdot\vec b=a_1b_1+a_2b_2+a_3b_3,\quad \text{proj}_{\vec b}\vec a=\frac{\vec a\cdot\vec b}{|\vec b|}\]
Vector Algebra
The scalar (dot) product of \(\vec a\) and \(\vec b\) is \(\vec a\cdot\vec b=|\vec a||\vec b|\cos\theta\), a number. In components \(\vec a\cdot\vec b=a_1b_1+a_2b_2+a_3b_3\).
Example: \(\vec a=\hat i+2\hat j+2\hat k\), \(\vec b=2\hat i-\hat j+2\hat k\): \(\vec a\cdot\vec b=2-2+4=4\), \(|\vec a|=|\vec b|=3\), so \(\cos\theta=\frac49\).
\[\vec a\cdot\vec b=a_1b_1+a_2b_2+a_3b_3,\quad \text{proj}_{\vec b}\vec a=\frac{\vec a\cdot\vec b}{|\vec b|}\]
\(|\vec a+\vec b|^2=|\vec a|^2+|\vec b|^2+2\vec a\cdot\vec b\); \((\vec a+\vec b)\cdot(\vec a-\vec b)=|\vec a|^2-|\vec b|^2\).
Projection of \(\vec a\) on \(\vec b\) divides by \(|\vec b|\), not \(|\vec a|\).
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